How do you integrate (re^r/2)dr ?
Here is what I have so far, I think I am making a mistake with the integration of e^r/2.
(re^r/2)dr u = r dV = e^r/2dr
du = dr V = (1/2)e^r/2
uV - (integral of) Vdu
so:
(1/2)re^r/2 - (integral of)(1/2)e^r/2 dr
(1/2)re^r/2 - (1/4)e^r/2 + c