How do you integrate (re^r/2)dr ?

Here is what I have so far, I think I am making a mistake with the integration of e^r/2.

(re^r/2)dr u = r dV = e^r/2dr

du = dr V = (1/2)e^r/2

uV - (integral of) Vdu

so:

(1/2)re^r/2 - (integral of)(1/2)e^r/2 dr

(1/2)re^r/2 - (1/4)e^r/2 + c