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Thread: Area of Region

  1. September 10th 2009, 08:03 AM #1
    loutja35
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    Area of Region

    #1.)

    Find the are of the region bounded by
    y= 1 divided by x^2, y=x, and y=8x, for x>0
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  2. September 10th 2009, 12:11 PM #2
    skeeter
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    Quote Originally Posted by loutja35 View Post
    #1.)

    Find the are of the region bounded by
    y= 1 divided by x^2, y=x, and y=8x, for x>0
    make a sketch

    find the intersection x-values ...

    \frac{1}{x^2} = 8x at x = \frac{1}{2}

    \frac{1}{x^2} = x at x = 1

    x = 8x at x = 0

    set up the integral expressions ...

    <br /> A = \int_0^{\frac{1}{2}} 8x - x \, dx + \int_{\frac{1}{2}}^1 \frac{1}{x^2} - x \, dx<br />
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