Assuming the sequence has a limit, call it "a".
Taking the limit on both sides of gives so which reduces to the quadratic equation . That has two solutions. Which of them the sequence converges to depends upon the initial value.
By the way, you could then show that the sequence does have a limit by showing it is increasing and has an upper bound.
What is the formula for the coefficients of a MacLaurin polynomial?Also another question..:
If f(x) is a function that is 8 times continuously differentiable such that the coefficient of x^5 in its 8th MacLaurin polynomial is 0.2, then f^5(0) =
Help would be much appreciated =)