a minimum of?
or does it mean something like?
1+9 =10
I guess you could do it as a trial error like that . . .
or you could do it the "calculus" way:
and then take the derivative and see where it goes to zero. *shrugs*
Well first of all let the two numbers be a and b.
Now if their sum is 10, then we can say
Now the seum of their squares is
let this equal another variable, say, y
so
substituting in for b from the equation established above, we get
rearrange
to find where y has a max/min, we have to fins dy/dx and let it equal 0
There you go, that's one of the two numbers, and the second one can be found with the first formula we established.
This kind of approach is best for these questions, if you're stuck always try and say "let this equal a and that equal b", and see where it takes you.