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Math Help - Limits Proof

  1. #1
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    Limits Proof

    The problem say prove this...

    limit→0 from the right

    Square root(x)[1+sin^2(2pi/x]=0
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  2. #2
    MHF Contributor chisigma's Avatar
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    The function ...

    f(x)= \sqrt{x} (1+\sin^{2} \frac{2\pi}{x}) (1)

    ... is the product of two terms. The first is \sqrt{x} which tends to zero if x tends to zero and the second for any value of x is forced to lie between 1 and 2. So is...

    \lim_{ x \rightarrow 0+} f(x)=0 (2)

    Kind regards

    \chi \sigma
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