1. Limits Proof

The problem say prove this...

limit→0 from the right

Square root(x)[1+sin^2(2pi/x]=0

2. The function ...

$f(x)= \sqrt{x} (1+\sin^{2} \frac{2\pi}{x})$ (1)

... is the product of two terms. The first is $\sqrt{x}$ which tends to zero if x tends to zero and the second for any value of x is forced to lie between 1 and 2. So is...

$\lim_{ x \rightarrow 0+} f(x)=0$ (2)

Kind regards

$\chi$ $\sigma$