The key is to exterminate the root, that is what annoys us, so for your first problem, put written backwards as and then compute

In the same fashion, can you compute your second integral?

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- September 9th 2009, 06:18 PM #1

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## New to Integration (and new to forum)

Hi guys, calculus is not my strong point and I'm having a bit of difficulty trying to integrate these problems:

integrate: x(x-2)/(x-1)^3

int: x/(9-x)^1/2

Can I use u substitution here?

and also I'm not sure how to go about these problems, where I have to find the area under the curve bounded the given numbers:

1/xlnx where b=e^2 and a=e

x-1/(x+1) where b=1 and a=0

I would really appreciate it!

<3

from a humanities major

- September 9th 2009, 06:47 PM #2

- September 9th 2009, 07:17 PM #3

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- September 9th 2009, 07:18 PM #4

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- September 9th 2009, 07:18 PM #5

- September 9th 2009, 07:36 PM #6

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thanks for replying so quickly!

I suppose I don't understand what you mean by the a+b/c = a/c +b/c. can I still do that when x is multiplied by (x-2)? Maybe I'm missing a step here.

x(x-2) x x-2

----------- ?=? ---------- + ---------

(x-1)^3 (x-1)^3 (x-1)^3

i'm sorry if i'm a little bit slow. I'm taking calc 2, and haven't taken calculus since high school.

- September 9th 2009, 07:45 PM #7

- September 9th 2009, 07:48 PM #8

- September 9th 2009, 07:50 PM #9

- September 9th 2009, 07:54 PM #10

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- September 9th 2009, 07:55 PM #11

- September 9th 2009, 08:03 PM #12

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- September 9th 2009, 08:24 PM #13

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- September 9th 2009, 08:25 PM #14

- September 9th 2009, 08:28 PM #15

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