# Thread: Difficult Limit

1. ## Difficult Limit

Hello all!

I just encountered this limit in my Calc homework, and had no idea as to what to do.

$\displaystyle \lim_{x \rightarrow 0} 2x^2\cot^2{7x}$

Thanks so much for any help you'd be able to provide,

Chikken

2. Originally Posted by Chikken
Hello all!

I just encountered this limit in my Calc homework, and had no idea as to what to do.

$\displaystyle \lim_{x\to 0}(x^2)tan^2(7x)$
Is that it.

3. No, sorry, I was having trouble with Latex until just now.

It's updated properly.

4. Can't you just convert it into:

$\displaystyle \lim_{x \rightarrow 0} 2x^2\frac{cos^2(7x)}{sin^2(7x)}$

and use l'hospital's rule?

5. Ah....yeah, that worked, just had to apply L'Hopital's Rule twice, to the converted form of the limit.

Came out to 2/49, but it was a simple enough calculation once I finally realized what I had to do haha.

University calc is quite a bit more demanding than IBHL was at my school, and it's only the first two weeks lol.

Thanks for the help, by the way!