Hello all!
I just encountered this limit in my Calc homework, and had no idea as to what to do.
$\displaystyle
\lim_{x \rightarrow 0} 2x^2\cot^2{7x}
$
Thanks so much for any help you'd be able to provide,
Chikken
Hello all!
I just encountered this limit in my Calc homework, and had no idea as to what to do.
$\displaystyle
\lim_{x \rightarrow 0} 2x^2\cot^2{7x}
$
Thanks so much for any help you'd be able to provide,
Chikken
Ah....yeah, that worked, just had to apply L'Hopital's Rule twice, to the converted form of the limit.
Came out to 2/49, but it was a simple enough calculation once I finally realized what I had to do haha.
University calc is quite a bit more demanding than IBHL was at my school, and it's only the first two weeks lol.
Thanks for the help, by the way!