$\displaystyle y=e^xsin(4e^{5x})$ hints please
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Originally Posted by iPod $\displaystyle e^xsin(5e^4)$ hints please $\displaystyle sin(5e^4)$ = constant $\displaystyle \frac{d}{dx}(ae^x) = ae^x$
i understood that, however the question i have written the 1st time was incorrect, please take another look
Originally Posted by iPod $\displaystyle y=e^xsin(4e^{5x})$ hints please try the product rule? f(x)=e^x f'(x)=e^x g(x)=(sin(4e^{5x})) g'(x)=(cos(4e^{5x}))(4e^{5x})(5)=20e^{5x}(cos(4e^{ 5x})) dy/dx=f(x)g'(x)+g(x)f'(x)
thanks very much, i got it now
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