The solution to this problem is proving to be elusive, any insight would be appreciated! The integral from x to x^2, with f(x) = t^2, and I'm looking for the derivative of that. Thanks!
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Originally Posted by N736RA The solution to this problem is proving to be elusive, any insight would be appreciated! The integral from x to x^2, with f(x) = t^2, and I'm looking for the derivative of that. Thanks! Would it not be $\displaystyle \frac{d}{dx}\left[\frac{1}{3}\left(t^3|^{x^2}_{x}\right)\right]$ ?
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right thats what I thought it was, could you also write that as : (1/3)(x^5+x^3) ? or am I missing another step somewhere?
mathitutor, thansk for that solution! That clears it up
Originally Posted by N736RA right thats what I thought it was, could you also write that as : (1/3)(x^5+x^3) ? or am I missing another step somewhere? No... Watch $\displaystyle \frac{d}{dx}\left[\frac{x^6-x^3}{3}\right]=\frac{d}{dx}(\frac{x^6}{3})-\frac{d}{dx}(\frac{x^3}{3})=6\cdot\frac{x^5}{3}-3\cdot\frac{x^2}{3}=2x^5-x^2$
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