The point (3,2,-1) lies equidistant from two parallel planes Psub1 and Psub2. Psub1 has equation 2x-y+2z+4=0. Find an equation for Psub2. Thank you very much.
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Originally Posted by Jenny20 The point (3,2,-1) lies equidistant from two parallel planes Psub1 and Psub2. Psub1 has equation 2x-y+2z+4=0. Find an equation for Psub2. Thank you very much. Hint, a parallel plane has equation, All you need to do if find .
Do you know the formula for the distance between a point and a plane?. The plane has equation The point: You have: Now, use the formula again and solve for k as PH said:
Hi galactus, solving what you gave : the result of k will be 4 again! So how can we get the equation of Psub2?
No, one of the answers is 4. There's another.
Hi galactus, Could you please show me how? Thank you very much.
Jenny20, I am sorry, but I gave you the entire equation. Solve for k. I don't what to seem 'short', but if you can't solve that, you shouldn't be in calc. What it amounts to is solving 4 is one of the answers. What's the other?.
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