Evaluate the definite integralusing the Fundamental Theorem of Calculus. You will need accuracy to at least 4 decimal places for your numerical answer to be accepted. You can also leave your answer as an algebraic expression involving square roots.
I understand the FTC when you have x in the limits but since there is no x I'm confused on how to solve this.
Thanks!
Originally Posted by Casas4
Evaluate the definite integralusing the Fundamental Theorem of Calculus. You will need accuracy to at least 4 decimal places for your numerical answer to be accepted. You can also leave your answer as an algebraic expression involving square roots.
I understand the FTC when you have x in the limits but since there is no x I'm confused on how to solve this.
Thanks!
Evaluate the definite integralusing the Fundamental Theorem of Calculus. You will need accuracy to at least 4 decimal places for your numerical answer to be accepted. You can also leave your answer as an algebraic expression involving square roots.
I understand the FTC when you have x in the limits but since there is no x I'm confused on how to solve this.
Thanks!![\int_5^6 \frac{6t^3}{\sqrt{2+3t^4}} \, dt = \left[\sqrt{2+3t^4}\right]_5^6](http://latex.codecogs.com/png.latex?\int_5^6 \frac{6t^3}{\sqrt{2+3t^4}} \, dt = \left[\sqrt{2+3t^4}\right]_5^6)
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