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Math Help - Fundamental Theorem of Calc. Integration

  1. #1
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    Fundamental Theorem of Calc. Integration

    Evaluate the definite integral
    using the Fundamental Theorem of Calculus. You will need accuracy to at least 4 decimal places for your numerical answer to be accepted. You can also leave your answer as an algebraic expression involving square roots.

    I understand the FTC when you have x in the limits but since there is no x I'm confused on how to solve this.
    Thanks!
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    Quote Originally Posted by Casas4 View Post
    Evaluate the definite integral
    using the Fundamental Theorem of Calculus. You will need accuracy to at least 4 decimal places for your numerical answer to be accepted. You can also leave your answer as an algebraic expression involving square roots.

    I understand the FTC when you have x in the limits but since there is no x I'm confused on how to solve this.
    Thanks!
    I=\sqrt{2+3t^4}+C
    I=\sqrt {2+3\times 6^4} - \sqrt {2+3\times 5^4}
    Last edited by mr fantastic; September 18th 2009 at 09:03 AM. Reason: Restored original post
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  3. #3
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    Quote Originally Posted by Casas4 View Post
    Evaluate the definite integral
    using the Fundamental Theorem of Calculus. You will need accuracy to at least 4 decimal places for your numerical answer to be accepted. You can also leave your answer as an algebraic expression involving square roots.

    I understand the FTC when you have x in the limits but since there is no x I'm confused on how to solve this.
    Thanks!
    \int_5^6 \frac{6t^3}{\sqrt{2+3t^4}} \, dt = \left[\sqrt{2+3t^4}\right]_5^6
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