# Math Help - Sin limit problem

1. ## Sin limit problem

I'm having trouble with finding the limit of (sinx)(lnsinx) as x approaches 0 from the positive side. Any suggestions? Thanks!

2. Why not try L'Hospital's rule? $sin(x) log(sin(x)) = \frac{log(sin(x))}{\frac{1}{sinx}}$. That limit has the indeterminate form $\frac{\infty}{\infty}$.

3. What he said

4. For x 'small enough' is $\sin x \approx x$ so that is...

$\lim_{ x \rightarrow 0+} \sin x \cdot \ln \sin x = \lim_{ x \rightarrow 0+} x \cdot \ln x = 0$

Kind regards

$\chi$ $\sigma$