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Math Help - System of equations

  1. #1
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    System of equations




    could someone please help with how youd want to solve this system? I have not taken a linear algebra course and have never dealt with a system like this.
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  2. #2
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    Your hyperlink lacks integrity.
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  3. #3
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    Quote Originally Posted by pickslides View Post
    Your hyperlink lacks integrity.

    A cos 210 + 200 cos Theta = 250 Cos 135 - 200 Cos 65
    A sin 210 + 200 sin Theta = 250 sin 135 - 200 sin 65
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  4. #4
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    Quote Originally Posted by ur5pointos2slo View Post
    A cos 210 + 200 cos Theta = 250 Cos 135 - 200 Cos 65
    A sin 210 + 200 sin Theta = 250 sin 135 - 200 sin 65
    The first thing I would do is go ahead and find those sines and cosines.
    Assuming that the arguments are degrees:
    cos(210)= cos(180+ 30)= -cos(30)= -\sqrt{3}/2.
    sin(210)= sin(180+ 30)= sin(30)= \frac{1}{2}
    cos(135)= cos(90+ 45)= -cos(45)= -\sqrt{2}/2
    sin(135)= sin(90+ 45)= sin(45)= \sqrt{2}/2
    cos(65) and sin(65) are the only ones that cannot be written in a simple form. Are you sure it wasn't sin(60) and cos(60)?
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  5. #5
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    Quote Originally Posted by HallsofIvy View Post
    The first thing I would do is go ahead and find those sines and cosines.
    Assuming that the arguments are degrees:
    cos(210)= cos(180+ 30)= -cos(30)= -\sqrt{3}/2.
    sin(210)= sin(180+ 30)= sin(30)= \frac{1}{2}
    cos(135)= cos(90+ 45)= -cos(45)= -\sqrt{2}/2
    sin(135)= sin(90+ 45)= sin(45)= \sqrt{2}/2
    cos(65) and sin(65) are the only ones that cannot be written in a simple form. Are you sure it wasn't sin(60) and cos(60)?
    Yes sir 100% sure it is 65 degrees.
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  6. #6
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    ok so now that I have found the cosines and sines..How would I go about solving this thing?
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