Originally Posted by
Pinklink for 5. i ended up with (x (7x^3 -5x^2-37x-35))/(x^4+5x^2-6) = 0..but that doesn't seem right
move the right fraction to the other side and cross-multiply ...
you should get $\displaystyle \textcolor{red}{7x^4 - 42x^2 - 35x = 0}$ after simplifying. you'll also get two nice solutions.
in 14 and 15 i don't know what the triangles mean
change $\displaystyle \textcolor{red}{\Delta x}$ to $\displaystyle \textcolor{red}{h}$ and work them.
I have never graphed functions with restrictions like in 16 and 17
#16 is a difference quotient ... note that $\displaystyle \textcolor{red}{f(x+h) = \frac{1}{x+h}}$
#17 are piecewise functions ... graph each piece for the x-values given. you should have graphed these in precalculus.
i think 13a. doesn't have a domain ... that is incorrect.
$\displaystyle \textcolor{red}{y = x^20}$ ... what values of x can you legally use?
i don't know what the symbols in 41-43 stand for
those are just piecewise functions like in #17 ... the bold garbage symbols are just that, garbage (big typos).