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Math Help - I hate calculus...please help

  1. #1
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    I hate calculus...please help

    The expression equals
    where , the exponent of , is:
    and , the exponent of , is:
    and finally , the exponent of , is:
    [NOTE: Your answers cannot be algebraic expressions.]


    The expression equals
    where r, the exponent of g, is:
    and s, the exponent of y, is:
    and k, the leading coefficient is:

    The expression
    equals
    where r, the exponent of h, is:
    and t, the exponent of s, is:
    and k, the leading coefficient is:


    The expression equals
    where , the leading coefficient, is:
    and , the exponent of , is:
    and , the exponent of , is:
    and finally , the exponent of , is:
    [NOTE: Your answers cannot be algebraic expressions.]

    hopefully after understanding these questions ill be able to do the others...
    Last edited by mr fantastic; September 7th 2009 at 01:34 PM.
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  2. #2
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    skeeter's Avatar
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    Quote Originally Posted by wannous View Post
    The expression equals
    where , the exponent of , is:
    and , the exponent of , is:
    and finally , the exponent of , is:
    [NOTE: Your answers cannot be algebraic expressions.]


    The expression equals
    where r, the exponent of g, is:
    and s, the exponent of y, is:
    and k, the leading coefficient is:

    The expression
    equals
    where r, the exponent of h, is:
    and t, the exponent of s, is:
    and k, the leading coefficient is:


    The expression equals
    where , the leading coefficient, is:
    and , the exponent of , is:
    and , the exponent of , is:
    and finally , the exponent of , is:
    [NOTE: Your answers cannot be algebraic expressions.]

    hopefully after understanding these questions ill be able to do the others...
    this isn't calculus, it's just knowing the exponent laws of algebra.

    perhaps you need a review?

    Exponents: Basic Rules
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  3. #3
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    Israel
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    (\frac{x^{-3}y^4z^4}{(xy)^{-6}z^6})^{-3} = (\frac{x^{-3}y^4z^4}{x^{-6}y^{-6}z^6})^{-3} = (x^{-3-(-6)}y^{4-(-6)}z^{4-6})^{-3}

    = (x^3y^{10}z^{-2})^{-3} = x^{3-3}y^{10-3}z^{-3-3} = y^7z^{-6} = \frac{y^7}{z^6} \Rightarrow  r = 0; s=7;t=-6

    For the second, you should note that the expression inside the root is the same; Let u=729g^2y^2 , then: (729y^2g^2)^{\frac{1}{3}} (729y^2g^2)^{\frac{1}{2}} = u^{\frac{1}{3}}*u^{\frac{1}{2}}

    Can you continue from here?

    E: Oops, didn't see skeeter's post. Anyway, this is indeed just exponentiation rules.
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