< is angle sign in this case.
C is the resultant of the forces, 2A and 3B, that is C=2A+3B.
If A=300N<43 deg. and C =100N<97 deg. , use the component method to determine the magnitude and direction of B.
I am not sure if this problem is done correctly. Here is my attempt:
Ax = 600 cos 43 = 438N
Ay = 600 sin 43 = 409 N
Bx = ?
By = ?
Cx=100 sin 43 = 68 N
Cy=100 cos 43 = 73 N
438 + Bx= 68
409 + By = 73
B = sqrt( (-370)^2 + (-336)^2) So B = 499N
Is this correct? What about the 3B?