Thread: Lines in a Plane 13

Find a vector equation for the line through the origin that intersects both of the lines r=(2,-16,19)+t(1,1,-4) and r=(14,19,-2)+u(-2,1,2).

This is my work so far, but I can't seem to find the correct answer.

d1=(1,1,-4)
d2=(-2,1,2)

i'm stuck here..

Let r=(0,0,0)+v(a,b,c) the requested line

There exists a value for v, say and another value, say such that








Let





Solving gives




You can chose one of the coordinates a, b or c
If you chose a = 17 then b = -15 and c = -20

how did you get a=17?

I can't seem to figure out how you got your final answer, the a=17 then b=-15 and c =-20.. this step before this, or to get to this a=17, where did it come from?

Can you, running-gag, or someone else clarify it for me? please and thank you

As I said before you can chose any value for a
I have chosen a=17 because it makes the other values very simple

The coordinates of the intersect with r=(2,-16,19)+t(1,1,-4) is given for t=121/16, therefore (153/16,-135/16,-180/16)

If you chose a=17, you will get b=-15, c=-20 and v1=9/16
But if you chose a=34, you will get b=-30, c=-40 and v1=9/32

This does not change the coordinates of the intersect (v1a,v1b,v1c) and does not change either the line since r=(0,0,0)+v(17,-15,-20) and r=(0,0,0)+v(34,-30,-40) are the same line

ok, so i could even choose a=1 and then find v1, and then find b and c right?
so
a=1
v1=153/16

b=-135/153

c=-180/153

running-gag? can you let me know about what i said above? just this last question

Thanks so much for your help by the way

That's correct !