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Math Help - another simpsons rule

  1. #1
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    another simpsons rule

    In the picture attached, I have modeled a lake to have a total area of 50.35cm^2.

    My intervals were 2.375cm, and the top area came out to 26.125cm^2, and the bottom to 24.225cm^2.

    The scale used is 2.375cm = 10m

    If I now have my total area in cm^2, how can I now convert this back to meters squared using this scale?
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  2. #2
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    ?? cm \cdot \frac{m}{100\;cm}\;=\;m

    cm^{2} \cdot \left[\frac{m}{100\;cm}\right]^{2}\;=\;m^{2}

    Do we dare suggest how one might convert such a thing if it were a "volume" problem?
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  3. #3
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    I do not understand how to do this using my scale.

    I know my area is 50.35cm^2, but I am having trouble converting this using the scale: 2.375cm = 10m.
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  4. #4
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    The usual conversion for cm to m is as I have provided it, 100 cm = 1 m. The conversion from cm to m is as I have demonstrated it. This is just working in standard metric units.

    Your problem is just working with a different unit conversion. You have 2.375 cm = 10 m. Just use this conversion in EXACTLY the same way as the standard conversion.

     <br />
50.35\;cm^{2} \cdot \left[\frac{10\;m}{2.375\;cm}\right]^{2}\;=\;??<br />

    The important thing is to get the units in the right place, numerator or denominator.
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