# another simpsons rule

• September 4th 2009, 07:04 PM
Mr.Ree
another simpsons rule
In the picture attached, I have modeled a lake to have a total area of 50.35cm^2.

My intervals were 2.375cm, and the top area came out to 26.125cm^2, and the bottom to 24.225cm^2.

The scale used is 2.375cm = 10m

If I now have my total area in cm^2, how can I now convert this back to meters squared using this scale?
• September 4th 2009, 09:14 PM
TKHunny
?? $cm \cdot \frac{m}{100\;cm}\;=\;m$

$cm^{2} \cdot \left[\frac{m}{100\;cm}\right]^{2}\;=\;m^{2}$

Do we dare suggest how one might convert such a thing if it were a "volume" problem?
• September 4th 2009, 09:23 PM
Mr.Ree
I do not understand how to do this using my scale.

I know my area is 50.35cm^2, but I am having trouble converting this using the scale: 2.375cm = 10m.
• September 5th 2009, 09:11 AM
TKHunny
The usual conversion for cm to m is as I have provided it, 100 cm = 1 m. The conversion from cm to m is as I have demonstrated it. This is just working in standard metric units.

Your problem is just working with a different unit conversion. You have 2.375 cm = 10 m. Just use this conversion in EXACTLY the same way as the standard conversion.

$
50.35\;cm^{2} \cdot \left[\frac{10\;m}{2.375\;cm}\right]^{2}\;=\;??
$

The important thing is to get the units in the right place, numerator or denominator.