I have this function:

I(a)= the integral from 0 to 1 of [x^(a)-x^(b)]/[ln(x)] where a > b > -1.

Using the fact that I(b) = 0, how would I show that I(a)= ln[(a+1)/(b+1)]?

Thank you for any help.

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- Jan 15th 2007, 12:12 PMJames234Integration
I have this function:

I(a)= the integral from 0 to 1 of [x^(a)-x^(b)]/[ln(x)] where a > b > -1.

Using the fact that I(b) = 0, how would I show that I(a)= ln[(a+1)/(b+1)]?

Thank you for any help.