$\displaystyle f(x)= \ln{(5x^2+3x-6)}$ is this right? $\displaystyle f'(x) = \frac{1}{5x^2+3x-6)}\cdot(10x+3)$ which is $\displaystyle \frac{10x+3}{5x^2+3x-6}$
Follow Math Help Forum on Facebook and Google+
Hey, Originally Posted by el123 $\displaystyle f(x)= \ln{(5x^2+3x-6)}$ is this right? $\displaystyle f'(x) = \frac{1}{5x^2+3x-6)}\cdot(10x+3)$ which is $\displaystyle \frac{10x+3}{5x^2+3x-6}$ yes, that is correct.
View Tag Cloud