This is probably pretty easy and I'm just over-thinking it, but I have no clue what to do for this problem.

If $\displaystyle \lim_{x \to3} (3x-2)=7$, find $\displaystyle S$ such that $\displaystyle |(3x-2)-7|<0.003$ whenever $\displaystyle 0<|x-3|<S.$