And "u" substitution doesn't give me an ln. I doubt I'll be tested on this, but still wanted to know. Thanks Matt, the rule is something I need to know I guess.
Okay then, substitute $\displaystyle u = 1 + e^{-x}$. Get $\displaystyle du$ in terms of $\displaystyle x$ and $\displaystyle dx$ and see what happens.
And "u" substitution doesn't give me an ln. I doubt I'll be tested on this, but still wanted to know. Thanks Matt, the rule is something I need to know I guess.
yes it does, you get $\displaystyle -\int \frac 1 u du$ which is wot?