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Math Help - basic differential

  1. #1
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    basic differential

    given that rootx + root y = 3x

    show that dy/dx = (6rootx-1) (root y) / root x

    Im just sooo confused by it
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  2. #2
    MHF Contributor
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    Quote Originally Posted by ramzel View Post
    given that rootx + root y = 3x

    show that dy/dx = (6rootx-1) (root y) / root x

    Im just sooo confused by it
    Hi ramzel.

    What exactly is troubling you? You're familiar with basic derivatives, right?

    Your problem is find dy/dx, given that \sqrt{x}+\sqrt{y}=3x

    To start, you need to differentiate every term in that equation. The first and the last one are straightforward, but the middle term, \sqrt{y} is trickier. You must remember to multiply by dy/dx at the end of the normal derivative we are assuming y is really y(x), meaning a function of x.

    Anyway, show me what you can do and we'll get through it.
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  3. #3
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    Sorry i got it it was so simple....

    What i did was that i divided one side by 3x which got the equation very complex....
    when all i had to do was just differentiate

    Sorry about this
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