# Math Help - basic differential

1. ## basic differential

given that rootx + root y = 3x

show that dy/dx = (6rootx-1) (root y) / root x

Im just sooo confused by it

2. Originally Posted by ramzel
given that rootx + root y = 3x

show that dy/dx = (6rootx-1) (root y) / root x

Im just sooo confused by it
Hi ramzel.

What exactly is troubling you? You're familiar with basic derivatives, right?

Your problem is find dy/dx, given that $\sqrt{x}+\sqrt{y}=3x$

To start, you need to differentiate every term in that equation. The first and the last one are straightforward, but the middle term, $\sqrt{y}$ is trickier. You must remember to multiply by dy/dx at the end of the normal derivative we are assuming y is really y(x), meaning a function of x.

Anyway, show me what you can do and we'll get through it.

3. Sorry i got it it was so simple....

What i did was that i divided one side by 3x which got the equation very complex....
when all i had to do was just differentiate