given that rootx + root y = 3x
show that dy/dx = (6rootx-1) (root y) / root x
Im just sooo confused by it
Hi ramzel.
What exactly is troubling you? You're familiar with basic derivatives, right?
Your problem is find dy/dx, given that $\displaystyle \sqrt{x}+\sqrt{y}=3x$
To start, you need to differentiate every term in that equation. The first and the last one are straightforward, but the middle term, $\displaystyle \sqrt{y}$ is trickier. You must remember to multiply by dy/dx at the end of the normal derivative we are assuming y is really y(x), meaning a function of x.
Anyway, show me what you can do and we'll get through it.