Hi
it would be really great if someone could help me with the following problem. I seem to have a great thick fog descending and cannot find my way out!!
Prove that:
(pi^3)/48 <= integral [0,pi/2] x^2/(2-sinx) dx <= (pi^3)/24
To get the upper bound, consider where the integrand reaches its maximum value - what would be the value of the integral if the integrand were constantly equal to this maximum value?
Hi
it would be really great if someone could help me with the following problem. I seem to have a great thick fog descending and cannot find my way out!!
Prove that:
(pi^3)/48 <= integral [0,pi/2] x^2/(2-sinx) dx <= (pi^3)/24