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Math Help - average velocity over the time interval

  1. #1
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    average velocity over the time interval

    A stone is tossed in the air from ground level with an initial velocity of 15m/s. Its height at time t is h(t) = 15t - 4.9t^2 m.

    Compute the stone's average velocity over the time interval [1, 3.5].Average velocity ?

    I tried to solve it, but when time is '3.5' v became minus...
    Last edited by wnsghkghk; September 1st 2009 at 07:07 PM. Reason: i mean v not t
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  2. #2
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    Quote Originally Posted by wnsghkghk View Post
    A stone is tossed in the air from ground level with an initial velocity of 15m/s. Its height at time t is h(t) = 15t - 4.9t^2 m.

    Compute the stone's average velocity over the time interval [1, 3.5].Average velocity ?

    I tried to solve it, but when time is '3.5' t became minus...
    \bar{v} = \frac{h(3.5) - h(1)}{3.5 - 1}<br />

    \bar{v} = \frac{h(3.5) - h(1)}{3.5 - 1} = -7.05 m/s
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  3. #3
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    Quote Originally Posted by wnsghkghk View Post
    A stone is tossed in the air from ground level with an initial velocity of 15m/s. Its height at time t is h(t) = 15t - 4.9t^2 m.

    Compute the stone's average velocity over the time interval [1, 3.5].Average velocity ?

    I tried to solve it, but when time is '3.5' t became minus...
    "t" is 3.5 which is NOT negative. I presume you mean that v is negative- and there is nothing wrong with that.
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  4. #4
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    ughhhhhhhhh I put just 7.05 not -7.05
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