Estimate the surface are of the figure below using the Trapezoidal Rule.
I did:
(40-0)/(2(4))[6+2(5)+2(4)+2(5)+5]
5[39]=195 ft^2
The thing is, apparently the correct answer is 250 ft^2 and I don't know why.
Any help is greatly appreciated
Estimate the surface are of the figure below using the Trapezoidal Rule.
I did:
(40-0)/(2(4))[6+2(5)+2(4)+2(5)+5]
5[39]=195 ft^2
The thing is, apparently the correct answer is 250 ft^2 and I don't know why.
Any help is greatly appreciated
Can you explain the source of the formula you are using - I'm confused by the 40-0/2(4) bit at the start, and how you got that to equal 5.
Also, I suspect that what you've done is ignored the bits at the ends - but I don't know how you were told to estimate those.
That's cause you have the rule wrong:
$\displaystyle (\frac{b-a}{2n})[f(x_0) + 2f(x_1) + 2f(x_2) +...+ 2f(x_{n-1}) + f(x_n)]$
Trapezoidal rule - Wikipedia, the free encyclopedia
It should be twice every inner term like I have written.
Yes. The distance from the left vertical line to the right vertical line is 40 but it looks like the entire region goes from 0 to 60. (The "trapezoids" on the left and right will be triangles. If it were me, instead of using the "trapezoid rule" formula, I would estimate the areas of the four trapezoids and two triangles involved and add them. Doing that I get 250.)