Prove that $\displaystyle \frac{d}{dx}(csc x) = -csc x cot x$ Ho do I prove that?
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Originally Posted by yoman360 Prove that $\displaystyle \frac{d}{dx}(csc x) = -csc x cot x$ Ho do I prove that? Note that $\displaystyle \csc x=\frac{1}{\sin x}$. Now apply the quotient rule. Have a shot at it, and report back if you still have problems!
Originally Posted by Chris L T521 Note that $\displaystyle \csc x=\frac{1}{\sin x}$. Now apply the quotient rule. Have a shot at it, and report back if you still have problems! Wow I couldn't believe it was that easy. Thanks so much
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