How can I solve quadratic equation using TI-83 plus?

Printable View

- December 24th 2008, 01:30 PMDiligent_LearnerHow can I solve quadratic equation using TI-83 plus?
How can I solve quadratic equation using TI-83 plus?

- December 24th 2008, 04:21 PMJhevon
- December 24th 2008, 06:33 PMJameson
This is actually a fairly easy program to write and a good exercise in BASIC, or something similar which the TI-83 uses. I don't have one in front of me, but I'll try to remember the syntax from memory - it might a little off.

ClearHome

Disp "Ax^2+Bx+C"

Input A

Input B

Input C

If sqrt{B^2-4AC}<0

Then

Disp "Non-real answer"

End

Else

sqrt{B^2-4AC} -> D

(-B+D)/(2A) -> M

(-B-D)/(2A) -> N

Disp "Roots are:"

Disp M->DispFrac

Disp N->DispFrac

End

That's the idea of it, probably with a lot of errors though. :) Just having some fun. - December 29th 2008, 05:06 AMearboth
Have a look here: http://www.mathhelpforum.com/math-he...-equation.html

If you want to get the real solutions only you still can use the SOLVER of the TI83: MATH 0: SOLVER - December 29th 2008, 08:50 AMduydaniel