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Math Help - Ti-84 Graphing Nint

  1. #1
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    Ti-84 Graphing Nint

    While trying to graph NINT, I keep getting the wrong graph.

    I'm trying to graph \sqrt{ 1 + sin^2 x} on the interval [0,3].
    I first got a straight line graphing:
    fnint(the function, x, 0, 3)
    Then I looked at my book and changed the x-res to increase speed.
    Now the function looked like an line that is increasing.
    I had put in:
    fnint(the function, x, 0, x)

    What should I do?
    Thanks!
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  2. #2
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    Quote Originally Posted by Truthbetold View Post
    While trying to graph NINT, I keep getting the wrong graph.

    (1) I'm trying to graph \sqrt{ 1 + sin^2 x} on the interval [0,3].


    I first got a straight line graphing:
    (2) fnint(the function, x, 0, 3)
    ...
    I don't know what went wrong:

    to #1: I've attached the screenshots of the graph.

    to #2: The command fnInt is used to calculate the integral

    \int_0^3 \sqrt{1+\sin^2(x)} dx

    which will yield one real number. See attachment.
    Attached Thumbnails Attached Thumbnails Ti-84 Graphing Nint-fnint_command.gif  
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