Thread: HP50g normal distribution function question

Hi ,

I just got a new HP50g and not sure how to solve for k.

Given P(X<k)=0.9573 .....(normal distribution)

Eg. using UTPN function for P(X<1)=0.8413:

UTPN(0,1,1)=0.1587 (ie the upper tail)

So 1-0.1587=0.8413 (ie lower tail)


Any help would be appreciated.

Thanks in advance,
Neverquit

Hi

how do I solve this?

P(X<k)=0.9573

Mean =0
SD=1

Best regards,

Neverquit


Moderator edit: Moved from Probability and Statistics subforum (see post #3).

Look at any normal distribution table, you'll inmediately find .

Hi but I am trying to do it on my HP50g.

Regards,
Neverquit

Originally Posted by Neverquit

Hi but I am trying to do it on my HP50g.

In that case, I can't help you. HP50g is not a friend of mine

Originally Posted by Neverquit

Hi but I am trying to do it on my HP50g.

Regards,
Neverquit

In the first instance you either go to the manual (which no doubt will be available for download on the HP website) or ask your instructor.

Originally Posted by Neverquit

Hi

how do I solve this?

P(X<k)=0.9573

Mean =0
SD=1

Best regards,

Neverquit


Moderator edit: Moved from Probability and Statistics subforum (see post #3).

You want to solve the equation:

UTPT(0,1,x)=0.0427

You can do this by trial and error, or look at using the numerical equation solver described in chapter 6 of the manual.

To get you started UTPT(0,1,1.7)~=0.0445655, and UTPT(0,1,1.8)~= 0.0359303, so the required solution is in the interval (1.7,1.8)


CB

Thanks Captain Black