Hi
how do I solve this?
P(X<k)=0.9573
Mean =0
SD=1
Best regards,
Neverquit
Moderator edit: Moved from Probability and Statistics subforum (see post #3).
Hi ,
I just got a new HP50g and not sure how to solve for k.
Given P(X<k)=0.9573 .....(normal distribution)
Eg. using UTPN function for P(X<1)=0.8413:
UTPN(0,1,1)=0.1587 (ie the upper tail)
So 1-0.1587=0.8413 (ie lower tail)
Any help would be appreciated.
Thanks in advance,
Neverquit
Hi
how do I solve this?
P(X<k)=0.9573
Mean =0
SD=1
Best regards,
Neverquit
Moderator edit: Moved from Probability and Statistics subforum (see post #3).
You want to solve the equation:
UTPT(0,1,x)=0.0427
You can do this by trial and error, or look at using the numerical equation solver described in chapter 6 of the manual.
To get you started UTPT(0,1,1.7)~=0.0445655, and UTPT(0,1,1.8)~= 0.0359303, so the required solution is in the interval (1.7,1.8)
CB