HP50g normal distribution function question

Hi ,

I just got a new HP50g and not sure how to solve for k.

Given P(X<k)=0.9573 .....(normal distribution)

Eg. using UTPN function for P(X<1)=0.8413:

UTPN(0,1,1)=0.1587 (ie the upper tail)

So 1-0.1587=0.8413 (ie lower tail)


Any help would be appreciated.

Thanks in advance,
Neverquit

Hi

how do I solve this?

P(X<k)=0.9573

Mean =0
SD=1

Best regards,

Neverquit


Moderator edit: Moved from Probability and Statistics subforum (see post #3).

Look at any normal distribution table, you'll inmediately find .

Hi but I am trying to do it on my HP50g.

Regards,
Neverquit

Quote:

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Originally Posted by Neverquit

Hi but I am trying to do it on my HP50g.

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In that case, I can't help you. HP50g is not a friend of mine :)

Quote:

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Originally Posted by Neverquit

Hi but I am trying to do it on my HP50g.

Regards,
Neverquit

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In the first instance you either go to the manual (which no doubt will be available for download on the HP website) or ask your instructor.

Quote:

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Originally Posted by Neverquit

Hi

how do I solve this?

P(X<k)=0.9573

Mean =0
SD=1

Best regards,

Neverquit


Moderator edit: Moved from Probability and Statistics subforum (see post #3).

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You want to solve the equation:

UTPT(0,1,x)=0.0427

You can do this by trial and error, or look at using the numerical equation solver described in chapter 6 of the manual.

To get you started UTPT(0,1,1.7)~=0.0445655, and UTPT(0,1,1.8)~= 0.0359303, so the required solution is in the interval (1.7,1.8)


CB

Thanks Captain Black