Solve the equation, e^x=4sinx ; x is greater than 0, less than 2pi.
how do i figure this out, and i have my ti-83 with me.
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Solve the equation, e^x=4sinx ; x is greater than 0, less than 2pi.
how do i figure this out, and i have my ti-83 with me.
Hello,
If you use your TI-83, you could simply punch in the function:
The x you are searching for is the x-value at the intersection between the graphs ofand
.
Can you input 'Ans' in your calculator (portable)? That means it can memorize the value obtained before and use the value in other calculation.
Set it to be about![]()
Then input
and press ' Enter' followed by ' Enter' ,' Enter',' Enter',' Enter',.... until no observable change on the screen , then the value displayed on it is the solution . It is
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The key to find out the solution is to put one of the variableas the subject . Here we can put
or
I also obtain the other solution ,