# TI-89 Integration

• Feb 24th 2010, 07:38 PM
sfskseg
TI-89 Integration
I've been using a TI-89 to check my work in my calc class, but I'm not sure how to enter one of the problems. It is:

integrate (from 0 to 16) (x^3 dx)/(x^2+32x+256)

I've never entered dx in the integrand before so is there a way to do it?

sfskseg
• Feb 24th 2010, 07:59 PM
Prove It
Quote:

Originally Posted by sfskseg
I've been using a TI-89 to check my work in my calc class, but I'm not sure how to enter one of the problems. It is:

integrate (from 0 to 16) (x^3 dx)/(x^2+32x+256)

I've never entered dx in the integrand before so is there a way to do it?

sfskseg

Note that $\int{\frac{x^3\,dx}{x^2 + 32x + 256}} = \int{\frac{x^3}{x^2 + 32x + 256}\,dx}$.

So just enter it as you normally would without the $dx$.
• Feb 25th 2010, 01:45 AM
mr fantastic
Quote:

Originally Posted by sfskseg
I've been using a TI-89 to check my work in my calc class, but I'm not sure how to enter one of the problems. It is:

integrate (from 0 to 16) (x^3 dx)/(x^2+32x+256)

I've never entered dx in the integrand before so is there a way to do it?

sfskseg

Get $\int($ from the F3 menue. Then:

$\int($ x^3/(x^2 + 32x + 256), x, 0, 16)
• Sep 7th 2010, 10:02 PM
matheagle
It's easier to just ban these from class