solving logs with calculator

**VNVeteran** · November 20th 2009, 05:07 PM

how do i plug in f(x)=log2 x where x=32

**Rapha** · November 20th 2009, 09:26 PM

Originally Posted by VNVeteran

how do i plug in f(x)=log2 x where x=32

What kind of calculator do you have?
If the $log_2$ -key is missing use ln(x) divided by ln(2) instead.

Because $log_2 x =\frac{ln(x)}{ln(2)}$

**mr fantastic** · November 20th 2009, 09:51 PM

Originally Posted by VNVeteran

how do i plug in f(x)=log2 x where x=32

Are you meant to use a calculator? Perhaps you're meant to notice that 32 = 2^5.

**VNVeteran** · November 21st 2009, 04:04 PM

Originally Posted by Rapha

What kind of calculator do you have?
If the $log_2$ -key is missing use ln(x) divided by ln(2) instead.

Because $log_2 x =\frac{ln(x)}{ln(2)}$

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