What kind of calculator do you have?
If the $\displaystyle log_2$-key is missing use ln(x) divided by ln(2) instead.
Because $\displaystyle log_2 x =\frac{ln(x)}{ln(2)} $
Nov 20th 2009, 09:51 PM
mr fantastic
Quote:
Originally Posted by VNVeteran
how do i plug in f(x)=log2 x where x=32
Are you meant to use a calculator? Perhaps you're meant to notice that 32 = 2^5.
Nov 21st 2009, 04:04 PM
VNVeteran
Quote:
Originally Posted by Rapha
What kind of calculator do you have?
If the $\displaystyle log_2$-key is missing use ln(x) divided by ln(2) instead.
Because $\displaystyle log_2 x =\frac{ln(x)}{ln(2)} $
thank you so much now i know how to dot his with a calculator ahhahahhaahahahah(Rofl) chapter 3 here i come ahahahahahaahahahah OOHAOHAOHAOHAOHAOH HAHAHAHAHAHHAHAHA(Rofl)