# Superannuation

• July 8th 2009, 03:45 AM
nerdzor
Superannuation
$3000 is invest yearly at 9%pa which is paid each half year, for 18yrs. Find the amount of the investment after 18yrs • July 8th 2009, 02:05 PM pickslides $A = P \left(1+\frac{r}{100}\right)^n$ where $P= 3000, r = 9$ & $n = 18$ $A = 3000 \left(1+\frac{9}{100}\right)^{18}= \dots$ • July 8th 2009, 03:07 PM Soroban Hello, nerdzor! Quote:$3000 is invested yearly at 9% pa which is paid each half-year.
Find amount of the investment after 18 years.

This is an annuity.

Formula: . $A \:=\:D\!\cdot\!\frac{(1+i)^n-1}{i}$

. . where: . $\begin{Bmatrix}D &=& \text{periodic deposit} \\ i &=& \text{periodic interest rate} \\ n &=& \text{number of periods} \\ A &=& \text{final amount} \end{Bmatrix}$

We have: . $D \:=\:3000 \qquad i \:=\:\frac{9\%}{2} \:=\:0.045 \qquad n \:=\: 36$
Hence: . $A \;=\;3000\!\cdot\!\frac{1.045^{36}-1}{0.045} \;=\;258491.8974$

The investment will be worth $\258,\!491.90$