the force of mortality is given by

μ(x) = 1/(100-x) ,for 0 < x < 100

compute

a.°e96:2l (the ° is supposed to be above the e) (line supposed to be above the 2)

b. e96:2l (line supposed to be above the 2, no dot this time)

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- May 5th 2009, 08:25 PMplm2eforce of mortality
the force of mortality is given by

**μ(x) = 1/(100-x) ,****for 0 < x < 100**

**compute**

**a.**°e96:2l (the ° is supposed to be above the e) (line supposed to be above the 2)

b. e96:2l (line supposed to be above the 2, no dot this time)

- May 8th 2009, 03:47 AMmr fantastic
- May 10th 2009, 11:05 AMTKHunny
Sorry, I don't drop by often enough...

b. is easy enough. Find $\displaystyle _{1}p_{96}$ + $\displaystyle _{2}p_{96}$ = $\displaystyle _{1}p_{96}$ + $\displaystyle _{1}p_{96}$*$\displaystyle _{1}p_{97}$

Usually, the complete expectation is taken to be 1/2 greater than the curtate expectation, but you may wish to work the intregrals for the exact values.

You will need the exact relationship between $\displaystyle \mu_{x}\;and\;_{t}p_{x}$