force of mortality

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• May 5th 2009, 08:25 PM
plm2e
force of mortality
the force of mortality is given by

μ(x) = 1/(100-x) ,for 0 < x < 100

compute
a. °e96:2l (the ° is supposed to be above the e) (line supposed to be above the 2)

b. e96:2l (line supposed to be above the 2, no dot this time)
• May 8th 2009, 03:47 AM
mr fantastic
Quote:

Originally Posted by plm2e
the force of mortality is given by

μ(x) = 1/(100-x) ,for 0 < x < 100

compute
a. °e96:2l (the ° is supposed to be above the e) (line supposed to be above the 2)

b. e96:2l (line supposed to be above the 2, no dot this time)

You're most likely not getting any replies to these questions because no-one can understand what the notation means.
• May 10th 2009, 11:05 AM
TKHunny
Sorry, I don't drop by often enough...

b. is easy enough. Find $\displaystyle _{1}p_{96}$ + $\displaystyle _{2}p_{96}$ = $\displaystyle _{1}p_{96}$ + $\displaystyle _{1}p_{96}$*$\displaystyle _{1}p_{97}$

Usually, the complete expectation is taken to be 1/2 greater than the curtate expectation, but you may wish to work the intregrals for the exact values.

You will need the exact relationship between $\displaystyle \mu_{x}\;and\;_{t}p_{x}$