please see attached word doc for problem, I could not get all the symbols to properly display on the thread.

there are 2 problems, 1st uses the survival function and the second is using de moivre's law. any help would be appreciated

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- May 1st 2009, 07:21 AMplm2eLife Contingenciesplease see attached word doc for problem, I could not get all the symbols to properly display on the thread.

there are 2 problems, 1st uses the survival function and the second is using de moivre's law. any help would be appreciated - May 1st 2009, 01:50 PMmr fantastic
Many members do not open attached files of any sort - and with good reason.

It would be easier for everyone if you just typed your questions rather than attaching them as a word file. That way they can be easily seen and quoted.

If you want to help, it's in your own self-interest to make things as easy as possible for people. - May 2nd 2009, 07:27 AMplm2e
ok, sorry about that. I was trying to make it look neat.

You are given that*s*(*x*) = 1 - .01x^2 for 0 ≤ x ≤ 10 and l0 = 1000.

Find a.)*μ*(4) b.) °e8 (the ° is supposed to be above the e)

- May 2nd 2009, 11:04 AMplm2e

i think i figured it out if anyone can check my work.

a.

*μ*(4) = -s'(x)/s(x) = .08/.84 = .0952

b.

°e8 = E[T(8)] =**∫**(from 0 to infin) tp8 dt

=**∫**[1-.01(8+t)^2] / [1-.01(8^2)]

= .36**∫**1-.64-.16t-.01t^2 dt =

= [.36t-.08t^2-(.01/3)t^3]l (from 0 to 2) *[(.36)]

= (.72-.32-.27)*.36 = .1344 - May 3rd 2009, 06:32 PMTKHunny
a. I'd prefer the prettier 2/21.

b. Does that make sense? Curtate survival to age 9 is s(9)/s(8) = 0.528