P(X) = -60X2 + 1500X - 4000 - 1≤x≤25

This is the profit function and its domain,

can you please help me find

1) the value of X where there is a breakeven point

2) the value of X where profit be maximum

thankyou so very much!!!

Printable View

- Jan 21st 2009, 02:22 AMkarimwahabProfit function!
P(X) = -60X2 + 1500X - 4000 - 1

**≤**x**≤**25

This is the profit function and its domain,

can you please help me find

1) the value of X where there is a breakeven point

2) the value of X where profit be maximum

thankyou so very much!!! - Jan 21st 2009, 06:06 AMMush
The breakeven point is the point where there is no profit and no deficit. In other words, the poitns when . You find x values of this by finding the roots of the equation. Using the quadratic formula!

or

For the maximum, the first derivative of the function is 0. Solve for x, and then plug that x value into the original equation to find P(x) for that value of x. The 2nd derivative test will tell you whether you have a maximum or a minimum. (Although you will have a maximum, since your coefficients of x^2 is negative!)