DQ and IRC

• Jan 20th 2008, 05:14 PM
crazydaizy78
DQ and IRC
use the difference quotient, w/h=0.01 and estimate the instantaneous rate of change.

#10. P(r)=100(1+r)^2 where r=0.12

Can you show me how to set up to solve? I do not seem to grasp the idea of the letters and the corresponding #'s and where to place. :confused:

I don't have the actual answer for this problem, book only gives odds.
• Jan 21st 2008, 12:23 AM
Jhevon
Quote:

Originally Posted by crazydaizy78
use the difference quotient, w/h=0.01 and estimate the instantaneous rate of change.

#10. P(r)=100(1+r)^2 where r=0.12

Can you show me how to set up to solve? I do not seem to grasp the idea of the letters and the corresponding #'s and where to place. :confused:

I don't have the actual answer for this problem, book only gives odds.

you want $\frac {P(r + h) - P(r)}h$ (usually for instantaneous rate of change, limits are involved, however, since they gave us constant values for r and h, i assume they don't want us to use that)

so you want: $\frac {P(0.12 + 0.01) - P(0.12)}{0.01}$
• Jan 21st 2008, 01:58 AM
mr fantastic
Quote:

Originally Posted by crazydaizy78
use the difference quotient, w/h=0.01 and estimate the instantaneous rate of change.

#10. P(r)=100(1+r)^2 where r=0.12

Can you show me how to set up to solve? I do not seem to grasp the idea of the letters and the corresponding #'s and where to place. :confused:

I don't have the actual answer for this problem, book only gives odds.

Since you figured out this one (well done (Star) ), I'm betting that by now you've figured out the answer to this latest one too.