Suppose that the demand x(in units) for a product is x=10,000-100p, where pd dollars is the market price per unit. The consumer expenditure for the product is E=px=10,000p-100p^2

For what market price will expenditure be greatest?

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- July 27th 2013, 07:23 PMPerezjayPlease help!
Suppose that the demand x(in units) for a product is x=10,000-100p, where pd dollars is the market price per unit. The consumer expenditure for the product is E=px=10,000p-100p^2

For what market price will expenditure be greatest? - July 29th 2013, 11:28 AMebainesRe: Please help!
Are you familiar with finding the min or max of a function by setting its derivative equal to zero? Here you have E = 10000p-100p^2, so dE/dp = 10000-500p. Set this equal to zero, solve for p, and check that the result is a max and not a min by seeing if d^2E/dp^2 is positive or negative.

If you are not famiiar with calculus you can try plotting the graph for E=10000p-100p^2 and see if you can estimate what value of p makes E the largest. - July 29th 2013, 12:27 PMHallsofIvyRe: Please help!
This is a quadratic function that does not require the "derivative" (or even knowing what a "derivative" [b]is[b]) to find max or min. Instead "complete the square". A "perfect square" is of the form . Compare that to . Since "p" corresponds to "a", "-100p" corresponds to -2ax, thus a corresponds to 50, and then . To make a perfect square we need to add 2500. And, of course, to keep the actual value the same, we need to subtract 2500 as well.

That is, .

Recalling that a square is never negative, it follows that is never positive. So what is the maximum value for consumer expenditure and for what p does it have that maximum? - July 29th 2013, 02:22 PMebainesRe: Please help!
Interesting technique - thanks for that. But a couple of typos crept into the equation. I've taken the liberty of making the corrections below in red:

"That is,

.

Recalling that a square is never negative, it follows that is never positive.... "