Comparison Test and Geometric Series
Let a(n) = (n^2)/(2^n)
Prove that if n>=3, then:
(a(n+1))/(a(n)) <= 8/9
By using this inequality for n = 3,4,5,..., prove that:
a(n+3) <= ((8/9)^n)(a(3))
Using the comparison test and results concerning the convergence of the geometric series, show that:
The SUM(from n=1 to infinity) of a(n+3) is convergent.
Now use the shift rule to show that:
The SUM(from n=1 to infinity) of a(n) is convergent.
Shown that if you let n=3 then (a(n+1))/(a(n)) = 8/9
How do I then show that for all n>=3, (a(n+1))/(a(n)) <= 8/9
From then on I'm not quite sure :(
thanks for any help and sorry for the lack of LaTex, I'm on a phone haha
Re: Comparison Test and Geometric Series