1. investment

if an investment of \$ 25,000 accumulates to P27,500 in 18 months, find the single interest rate?

this is my attempt: 27,000 - 25,000 = 2000 / 18 then the quotient is divided by 25,000. is this possible?

2. Re: investment

I think it is

$\frac{27500-25000}{25000}=\frac{1}{10}=0.1\quad (\text{or}~10\%)$

3. Re: investment

[QUOTE=DeMath;736289]I think it is

$\frac{27500-25000}{25000}=\frac{1}{10}=0.1\quad (\text{or}~10\%)$[/QUOTE

thanks but... the key answer from the book said that it is 6 2/3 % hmmmmmmmm... im confused... im still solving it here huuhuhuuhuh

4. Re: investment

[QUOTE=rcs;736298]
Originally Posted by DeMath
I think it is

$\frac{27500-25000}{25000}=\frac{1}{10}=0.1\quad (\text{or}~10\%)$[/QUOTE

thanks but... the key answer from the book said that it is 6 2/3 % hmmmmmmmm... im confused... im still solving it here huuhuhuuhuh
Need to find the annual single interest rate

$\frac{1}{10}\cdot \frac{12}{18}=\frac{1}{10}\cdot \frac{2}{3}= \frac{1}{15}$, i.e. $\left(\frac{1}{15}\cdot 100\right)\!\%= \frac{20}{3}\%= 6\tfrac{2}{3}\%$ (annual rate).

5. Re: investment

Very unclear question.

25000(1 + i)^1.5 = 27500
(1 + i)^1.5 = 27500/25000
1 + i = (27500/25000)^(1/1.5) : remember that if a^p = b, then a = b^(1/p)
i = (27500/25000)^(1/1.5) - 1
i = .0656... : so annual rate = ~6.56%

Your 6 2/3% result assumes SIMPLE interest; if so, then SHOULD be specified in the problem statement.