if an investment of $ 25,000 accumulates to P27,500 in 18 months, find the single interest rate?
this is my attempt: 27,000 - 25,000 = 2000 / 18 then the quotient is divided by 25,000. is this possible?
if an investment of $ 25,000 accumulates to P27,500 in 18 months, find the single interest rate?
this is my attempt: 27,000 - 25,000 = 2000 / 18 then the quotient is divided by 25,000. is this possible?
[QUOTE=DeMath;736289]I think it is
$\displaystyle \frac{27500-25000}{25000}=\frac{1}{10}=0.1\quad (\text{or}~10\%)$[/QUOTE
thanks but... the key answer from the book said that it is 6 2/3 % hmmmmmmmm... im confused... im still solving it here huuhuhuuhuh
Very unclear question.
25000(1 + i)^1.5 = 27500
(1 + i)^1.5 = 27500/25000
1 + i = (27500/25000)^(1/1.5) : remember that if a^p = b, then a = b^(1/p)
i = (27500/25000)^(1/1.5) - 1
i = .0656... : so annual rate = ~6.56%
Your 6 2/3% result assumes SIMPLE interest; if so, then SHOULD be specified in the problem statement.