Deposits are made at the beginning of every month into a fund earning a nominal annual rate of 6% convertible monthly. The first deposit is 100 and deposit increase 2% every year.

Calculate the fund balance at the end of 10 years.

Okay. Here's my solution

$\displaystyle (1.06167^{9})(100)\ddot{s}_{0.005,12}\left(\frac{1-(\frac{1.02}{1.06167})^{10}}{1-\frac{1.02}{1.06167}}\right)=17,859.22$

Can someone verify this answer? Also, if there's a nicer, easier, or faster way to solve the problem I'd be interested in seeing it. Thanks