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Math Help - p-value! need done by 11:30

  1. #1
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    p-value! need done by 11:30

    According to the NY Times, college students spend on average 50 hrs p/week on the internet. Most college students think it is significantly different. It is known the standard deviation for the amount of time spent on the internet is 17.5. A sample of 100 students was taken and the avg. time spent on the net was 45 hrs. At the a=0.05, does this show a significant difference in the amount of time spent of the net from what the NY Times reported?

    A. pval = .9979 and a=0.05; do not reject H0
    B. p val = .0021 and a=.05; reject H0
    C. pval = .0021 and a= .025; reject H0
    D. 0.0025< p val < .001, reject H0
    E. none of the above
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  2. #2
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    Re: p-value! need done by 11:30

    I think option D looks good.
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