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Math Help - Superannuation

  1. #1
    Junior Member
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    Exclamation Superannuation

    Hey guys,

    I've been trying to solve this question for ages but I seem to get the same (but wrong) answer ....

    The equation I derive is the amount remaining = 200 000 x r^n - 1051.41 (r^n - 1)/(r - 1) [where r = interest = 3013 / 3000]. However, when I try what it is after 6 years (72 months - isn't it just subbing it in?), I keep on getting $184 428.94. That doesn't seem right at all.... which made my answer for the final question really really off (19 years?!??!)

    Thanks for your help!
    Attached Thumbnails Attached Thumbnails Superannuation-photo0262.jpg  
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  2. #2
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    Re: Superannuation

    I went to a mortage calculator on line and get a monthly payment of 1342 dollars per month.There is a CPR (capital recovery factor) which you can find on line where you can aso find how the factor is derived, Principal times factor = monthly repayment not including any other charges
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  3. #3
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    Re: Superannuation

    Quote Originally Posted by Sunyata View Post
    The equation I derive is the amount remaining = 200 000 x r^n - 1051.41 (r^n - 1)/(r - 1) [where r = interest = 3013 / 3000].
    Monthly payment is NOT 1051.41; should be 1336.32

    And r = .052/12 ; where does 3013/3000 come from?
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  4. #4
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    Re: Superannuation

    Re: Wilmer

    Are you sure about the monthly repayment? Because the question itself states it is?

    As for the 3013/3000, it's just the fraction of the decimal u get from diving 5.2 by 100 then 12...
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  5. #5
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    Re: Superannuation

    Quote Originally Posted by Sunyata View Post
    Are you sure about the monthly repayment? Because the question itself states it is?
    As for the 3013/3000, it's just the fraction of the decimal u get from diving 5.2 by 100 then 12...
    YES. Did you not read BJHopper's reply?
    He's correct with ~$1,342; 1342.108103 to be exact...
    My 1336.32 was assuming beginning of period payments...

    The formula is:
    P = A*R / [1 - 1/(1 + R)^N]
    where:
    P = monthly Payment (?)
    A = Amount borrowed (200000)
    N = Number of months (20*12 = 240)
    R = Rate per month (.052 / 12 = .0043333...)

    P = 200000 * .0043333 / [1 - 1 / (1 + .0043333)^240] = 1342.108103...

    You can easily confirm above by googling "loan payment formula".

    As far as "the question" stating 1051.41, I have no idea; we're not
    here to "guess" the intentions of your teacher!

    Using 3013/3000 gives 1.0043333... which is 1 + i, not i;
    I suggest you don't use that method: NOT standard.
    If your teacher insists on this method, have him/her fired
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