Find number of periods from annuity formula
I have attempted to separate the number of periods (n) from the following equation
pv (1 + i)^n + pmt (1 + i * type) [{(1 + i)^n - 1}/i] + fv = 0
Have I done this correctly? (Thinking)
type has either a value of 0 for end of period payments and 1 for start of period payments
n = log[ { pmt * ( 1 + i * type) - fv * i } / { pmt * ( 1 + i * type) + pv * i } ] / log( 1 + i * type)
Thanks
Re: Find number of periods from annuity formula
Re: Find number of periods from annuity formula
Quote:
Originally Posted by
SpringFan25
I dont want to discourage questions, but wouldn't it be easier to test this yourself by substituting values, rather than ask us to repeat the algebra looking for errors?
I have not checked your answer in any detail, but look at your denominator:
log( 1 + i * type)
if type=0, then this is log(1). Log(1)=0 and so your expression is undefined (anything divided by 0 is undefined)./
I had a hunch there was something I did wrong
Well time to go back to the paper and pencil and redo the math
Will let you know if I come up with a correct solution
Thanks
Re: Find number of periods from annuity formula
Finally got it working
Thanks
Re: Find number of periods from annuity formula
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Re: Find number of periods from annuity formula
Quote:
Originally Posted by
bradhows
My site provides complete access Edmonton Real Estate
Are spammers allowed on this forum
Your site is a blog about real estate, what the heck that got to do with finding number of periods in an annuity (Punch)