i = .04543
[1000(1 + i)] * (1 + 3i/2)^4 = 1360.86738....
An investment of $1000 accumulates to $1360.86 at the end of 5 years. If the force of interest is during the first year and in each subsequent year, find the equivalent effective annual interest rate in the second year.
Not sure how to proceed, basically all i can think of is
so cant think of a function for that i should be using to integrate..