# Math Help - Force of Interest

1. ## Force of Interest

An investment of $1000 accumulates to$1360.86 at the end of 5 years. If the force of interest is $\delta$ during the first year and $1.5\delta$ in each subsequent year, find the equivalent effective annual interest rate in the second year.

Not sure how to proceed, basically all i can think of is
$1360.86=1000\cdot exp\left( \int^5_0 (...)dt \right)$

so cant think of a function for $\delta$ that i should be using to integrate..

2. i = .04543
[1000(1 + i)] * (1 + 3i/2)^4 = 1360.86738....