An investment of $1000 accumulates to $1360.86 at the end of 5 years. If the force of interest is $\displaystyle \delta$ during the first year and $\displaystyle 1.5\delta $ in each subsequent year, find the equivalent effective annual interest rate in the second year.

Not sure how to proceed, basically all i can think of is

$\displaystyle 1360.86=1000\cdot exp\left( \int^5_0 (...)dt \right)$

so cant think of a function for $\displaystyle \delta$ that i should be using to integrate..