Find present value as at january 2009 of a series of payments of 100 payable on first day of each month during years 2010,2011,2012. Assume effective rate of interestof 8% p.a(Giggle)

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- Nov 4th 2009, 12:19 PMmukrosaPresent Values
Find present value as at january 2009 of a series of payments of 100 payable on first day of each month during years 2010,2011,2012. Assume effective rate of interestof 8% p.a(Giggle)

- Nov 4th 2009, 04:28 PMTKHunny
- Nov 4th 2009, 07:31 PMmukrosaNot Sure
The payments were being made daily so mayb we ought to use[iΛ(364)][/]wat do u tnk?(Wink)

- Nov 4th 2009, 08:15 PMWilmer
Please get your problem CLEAR, then post it again (Nerd)

To see where you're at, can you answer this:

what is the present value of a series of 12 monthly payments,

starting in 1 month from now, at 12% annual compounded monthly? - Nov 4th 2009, 10:07 PMTKHunny
Often a monthly approximation is sufficient for payments made on the same day of each month.

Please be clear about the use fo the word "effective". Make sure you mean it. - Nov 4th 2009, 10:41 PMmukrosa
the monthly effective rate=0.11386 then i assume value of payments is 1 [(1-vΛn)/i=(1-(1/1.11386)Λ12)/0.11386=6.37469][/MATH

- Nov 5th 2009, 06:31 AMWilmer
NO. "12% annual compounded monthly" means 1% per month, so 1.01^12 - 1 = .126825 (12.6825% effective).

You assumed "12% effective annual compounded monthly", or:

(1 + i)^12 = 1.12 ; i = .009488... ; i * 12 = .11386...

Even at that, you need to use .009488 in your calculation, not .11386:

[1 - (1 / 1.009488)^12] / .009488 = 11.2915...

So, using $100 per month, present value is $1129.15

Your original problem states: "Assume effective rate of interestof 8% p.a".

The word "effective" means (1 + i)^12 = 1.08.

If instead it was: "Assume rate of interestof 8% p.a compounded monthly", then:

effective annual rate = (1 + .08/12)^12 - 1 = .0829995... (~8.3%)